1/4(12x-20)=1/3(15x-)

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Solution for 1/4(12x-20)=1/3(15x-) equation: 



1/4(12x-20)=1/3(15x-)

We move all terms to the left:

1/4(12x-20)-(1/3(15x-))=0



Domain of the equation: 4(12x-20)!=0

x∈R





Domain of the equation: 3(15x-))!=0

x∈R



We add all the numbers together, and all the variables

1/4(12x-20)-(1/3(+15x))=0

We calculate fractions


(3x(+)/(4(12x-20)*3(+15x)))+(-4x1/(4(12x-20)*3(+15x)))=0



We calculate terms in parentheses: +(3x(+)/(4(12x-20)*3(+15x))), so:

3x(+)/(4(12x-20)*3(+15x))

We add all the numbers together, and all the variables

3x0/(4(12x-20)*3(+15x))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-4x1/(4(12x-20)*3(+15x))), so:

-4x1/(4(12x-20)*3(+15x))

We multiply all the terms by the denominator


-4x1

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

3x-4x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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