1/4(12x-4)+3=2-x+12

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Solution for 1/4(12x-4)+3=2-x+12 equation: 



1/4(12x-4)+3=2-x+12

We move all terms to the left:

1/4(12x-4)+3-(2-x+12)=0



Domain of the equation: 4(12x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/4(12x-4)-(-1x+14)+3=0

We get rid of parentheses

1/4(12x-4)+1x-14+3=0

We multiply all the terms by the denominator


1x*4(12x-4)-14*4(12x-4)+3*4(12x-4)+1=0

Wy multiply elements

4x^2(1-56x(1+12x(1+1=0

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