1/4(16-8x)+8=2/3(-6x-12)

Solution for 1/4(16-8x)+8=2/3(-6x-12) equation:

1/4(16-8x)+8=2/3(-6x-12)

We move all terms to the left:

1/4(16-8x)+8-(2/3(-6x-12))=0


Domain of the equation: 4(16-8x)!=0

x∈R



Domain of the equation: 3(-6x-12))!=0

x∈R


We add all the numbers together, and all the variables

1/4(-8x+16)-(2/3(-6x-12))+8=0

We calculate fractions


(3x(-)/(4(-8x+16)*3(-6x-12)))+(-8x0/(4(-8x+16)*3(-6x-12)))+8=0


We calculate terms in parentheses: +(3x(-)/(4(-8x+16)*3(-6x-12))), so:

3x(-)/(4(-8x+16)*3(-6x-12))

We add all the numbers together, and all the variables

3x0/(4(-8x+16)*3(-6x-12))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)



We calculate terms in parentheses: +(-8x0/(4(-8x+16)*3(-6x-12))), so:

-8x0/(4(-8x+16)*3(-6x-12))

We multiply all the terms by the denominator


-8x0

We add all the numbers together, and all the variables

-8x

Back to the equation:

+(-8x)


We get rid of parentheses

3x-8x+8=0

We add all the numbers together, and all the variables

-5x+8=0

We move all terms containing x to the left, all other terms to the right

-5x=-8

x=-8/-5

x=1+3/5