1/4(16x+36)-9=-1/3(12x-9)

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Solution for 1/4(16x+36)-9=-1/3(12x-9) equation: 



1/4(16x+36)-9=-1/3(12x-9)

We move all terms to the left:

1/4(16x+36)-9-(-1/3(12x-9))=0



Domain of the equation: 4(16x+36)!=0

x∈R





Domain of the equation: 3(12x-9))!=0

x∈R



We calculate fractions


(3x1/(4(16x+36)*3(12x-9)))+(-(-4x1)/(4(16x+36)*3(12x-9)))-9=0



We calculate terms in parentheses: +(3x1/(4(16x+36)*3(12x-9))), so:

3x1/(4(16x+36)*3(12x-9))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-4x1)/(4(16x+36)*3(12x-9))), so:

-(-4x1)/(4(16x+36)*3(12x-9))

We add all the numbers together, and all the variables

-(-4x)/(4(16x+36)*3(12x-9))

We multiply all the terms by the denominator


-(-4x)

We get rid of parentheses

4x

Back to the equation:

+(4x)



We add all the numbers together, and all the variables

7x-9=0

We move all terms containing x to the left, all other terms to the right

7x=9

x=9/7

x=1+2/7

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