1/4(16x-20)=1/3(15x-12)

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Solution for 1/4(16x-20)=1/3(15x-12) equation: 



1/4(16x-20)=1/3(15x-12)

We move all terms to the left:

1/4(16x-20)-(1/3(15x-12))=0



Domain of the equation: 4(16x-20)!=0

x∈R





Domain of the equation: 3(15x-12))!=0

x∈R



We calculate fractions


(3x1/(4(16x-20)*3(15x-12)))+(-4x1/(4(16x-20)*3(15x-12)))=0



We calculate terms in parentheses: +(3x1/(4(16x-20)*3(15x-12))), so:

3x1/(4(16x-20)*3(15x-12))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-4x1/(4(16x-20)*3(15x-12))), so:

-4x1/(4(16x-20)*3(15x-12))

We multiply all the terms by the denominator


-4x1

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

3x-4x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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