1/4(16x-8)-8x=-1/3(x+9)

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Solution for 1/4(16x-8)-8x=-1/3(x+9) equation: 



1/4(16x-8)-8x=-1/3(x+9)

We move all terms to the left:

1/4(16x-8)-8x-(-1/3(x+9))=0



Domain of the equation: 4(16x-8)!=0

x∈R





Domain of the equation: 3(x+9))!=0

x∈R



We add all the numbers together, and all the variables

-8x+1/4(16x-8)-(-1/3(x+9))=0

We calculate fractions


-8x+(3xx/(4(16x-8)*3(x+9)))+(-(-4x1)/(4(16x-8)*3(x+9)))=0



We calculate terms in parentheses: +(3xx/(4(16x-8)*3(x+9))), so:

3xx/(4(16x-8)*3(x+9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-(-4x1)/(4(16x-8)*3(x+9))), so:

-(-4x1)/(4(16x-8)*3(x+9))

We add all the numbers together, and all the variables

-(-4x)/(4(16x-8)*3(x+9))

We multiply all the terms by the denominator


-(-4x)

We get rid of parentheses

4x

Back to the equation:

+(4x)



We add all the numbers together, and all the variables

-4x+3xx=0

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