1/4(2-3t)=5/6(t+1)

Solution for 1/4(2-3t)=5/6(t+1) equation:

1/4(2-3t)=5/6(t+1)

We move all terms to the left:

1/4(2-3t)-(5/6(t+1))=0


Domain of the equation: 4(2-3t)!=0

t∈R



Domain of the equation: 6(t+1))!=0

t∈R


We add all the numbers together, and all the variables

1/4(-3t+2)-(5/6(t+1))=0

We calculate fractions


(6tt/(4(-3t+2)*6(t+1)))+(-20t0/(4(-3t+2)*6(t+1)))=0


We calculate terms in parentheses: +(6tt/(4(-3t+2)*6(t+1))), so:

6tt/(4(-3t+2)*6(t+1))

We multiply all the terms by the denominator


6tt

Back to the equation:

+(6tt)



We calculate terms in parentheses: +(-20t0/(4(-3t+2)*6(t+1))), so:

-20t0/(4(-3t+2)*6(t+1))

We multiply all the terms by the denominator


-20t0

We add all the numbers together, and all the variables

-20t

Back to the equation:

+(-20t)


We get rid of parentheses

6tt-20t=0

We add all the numbers together, and all the variables

-20t+6tt=0