1/4(20-4a)=6+a

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Solution for 1/4(20-4a)=6+a equation: 



1/4(20-4a)=6+a

We move all terms to the left:

1/4(20-4a)-(6+a)=0



Domain of the equation: 4(20-4a)!=0

a∈R



We add all the numbers together, and all the variables

1/4(-4a+20)-(a+6)=0

We get rid of parentheses

1/4(-4a+20)-a-6=0

We multiply all the terms by the denominator


-a*4(-4a+20)-6*4(-4a+20)+1=0

Wy multiply elements

-4a^2(--24a(-+1=0

We use the square of the difference formula

-4a^2(+24a(-1=0

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