1/4(20-4y)=6-y

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Solution for 1/4(20-4y)=6-y equation:


y in (-oo:+oo)

(1/4)*(20-(4*y)) = 6-y // - 6-y

(1/4)*(20-(4*y))+y-6 = 0

(1/4)*(20-4*y)+y-6 = 0

1/4*(20-4*y)+y-6 = 0

1/4*(20-4*y)+y-6 = 0

5-6 = 0

-1 = 0

-1 = 0

y belongs to the empty set

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