1/4(20d+4)=5d

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Solution for 1/4(20d+4)=5d equation:



1/4(20d+4)=5d
We move all terms to the left:
1/4(20d+4)-(5d)=0
Domain of the equation: 4(20d+4)!=0
d∈R
We add all the numbers together, and all the variables
-5d+1/4(20d+4)=0
We multiply all the terms by the denominator
-5d*4(20d+4)+1=0
Wy multiply elements
-20d^2(2+1=0

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