1/4(20d+4)=5d+4

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Solution for 1/4(20d+4)=5d+4 equation: 



1/4(20d+4)=5d+4

We move all terms to the left:

1/4(20d+4)-(5d+4)=0



Domain of the equation: 4(20d+4)!=0

d∈R



We get rid of parentheses

1/4(20d+4)-5d-4=0

We multiply all the terms by the denominator


-5d*4(20d+4)-4*4(20d+4)+1=0

Wy multiply elements

-20d^2(2-16d(2+1=0

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