1/4(20x+4)=5x

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Solution for 1/4(20x+4)=5x equation: 



1/4(20x+4)=5x

We move all terms to the left:

1/4(20x+4)-(5x)=0



Domain of the equation: 4(20x+4)!=0

x∈R



We add all the numbers together, and all the variables

-5x+1/4(20x+4)=0

We multiply all the terms by the denominator


-5x*4(20x+4)+1=0

Wy multiply elements

-20x^2(2+1=0

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