1/4(2400+y)=1/8y+773

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Solution for 1/4(2400+y)=1/8y+773 equation: 



1/4(2400+y)=1/8y+773

We move all terms to the left:

1/4(2400+y)-(1/8y+773)=0



Domain of the equation: 4(2400+y)!=0

y∈R





Domain of the equation: 8y+773)!=0

y∈R



We add all the numbers together, and all the variables

1/4(y+2400)-(1/8y+773)=0

We get rid of parentheses

1/4(y+2400)-1/8y-773=0

We calculate fractions


8y/(32y^2+76800y)+(-4yy/(32y^2+76800y)-773=0

We calculate fractions

We do not support eypression: y^3

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