1/4(24x+32)-13=2/3(18x-9)

Solution for 1/4(24x+32)-13=2/3(18x-9) equation:

1/4(24x+32)-13=2/3(18x-9)

We move all terms to the left:

1/4(24x+32)-13-(2/3(18x-9))=0


Domain of the equation: 4(24x+32)!=0

x∈R



Domain of the equation: 3(18x-9))!=0

x∈R


We calculate fractions


(3x1/(4(24x+32)*3(18x-9)))+(-8x2/(4(24x+32)*3(18x-9)))-13=0


We calculate terms in parentheses: +(3x1/(4(24x+32)*3(18x-9))), so:

3x1/(4(24x+32)*3(18x-9))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)



We calculate terms in parentheses: +(-8x2/(4(24x+32)*3(18x-9))), so:

-8x2/(4(24x+32)*3(18x-9))

We multiply all the terms by the denominator


-8x2

We add all the numbers together, and all the variables

-8x^2

Back to the equation:

+(-8x^2)


We get rid of parentheses

-8x^2+3x-13=0

a = -8; b = 3; c = -13;
Δ = b2-4ac
Δ = 32-4·(-8)·(-13)
Δ = -407
Delta is less than zero, so there is no solution for the equation