1/4(2a-20)=3+6-5

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Solution for 1/4(2a-20)=3+6-5 equation:



1/4(2a-20)=3+6-5
We move all terms to the left:
1/4(2a-20)-(3+6-5)=0
Domain of the equation: 4(2a-20)!=0
a∈R
We add all the numbers together, and all the variables
1/4(2a-20)-4=0
We multiply all the terms by the denominator
-4*4(2a-20)+1=0
Wy multiply elements
-16a(2+1=0

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