1/4(2n-28)=10

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Solution for 1/4(2n-28)=10 equation:



1/4(2n-28)=10
We move all terms to the left:
1/4(2n-28)-(10)=0
Domain of the equation: 4(2n-28)!=0
n∈R
We multiply all the terms by the denominator
-10*4(2n-28)+1=0
Wy multiply elements
-40n(2+1=0

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