1/4(2q+5)=1/3(q+2)

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Solution for 1/4(2q+5)=1/3(q+2) equation: 



1/4(2q+5)=1/3(q+2)

We move all terms to the left:

1/4(2q+5)-(1/3(q+2))=0



Domain of the equation: 4(2q+5)!=0

q∈R





Domain of the equation: 3(q+2))!=0

q∈R



We calculate fractions


(3qq/(4(2q+5)*3(q+2)))+(-4q2/(4(2q+5)*3(q+2)))=0



We calculate terms in parentheses: +(3qq/(4(2q+5)*3(q+2))), so:

3qq/(4(2q+5)*3(q+2))

We multiply all the terms by the denominator


3qq

Back to the equation:

+(3qq)





We calculate terms in parentheses: +(-4q2/(4(2q+5)*3(q+2))), so:

-4q2/(4(2q+5)*3(q+2))

We multiply all the terms by the denominator


-4q2

We add all the numbers together, and all the variables

-4q^2

Back to the equation:

+(-4q^2)



We get rid of parentheses

-4q^2+3qq=0

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