1/4(2x+1)-7=1/2(2x-1)

Solution for 1/4(2x+1)-7=1/2(2x-1) equation:

1/4(2x+1)-7=1/2(2x-1)

We move all terms to the left:

1/4(2x+1)-7-(1/2(2x-1))=0


Domain of the equation: 4(2x+1)!=0

x∈R



Domain of the equation: 2(2x-1))!=0

x∈R


We calculate fractions


(2x2/(4(2x+1)*2(2x-1)))+(-4x2/(4(2x+1)*2(2x-1)))-7=0


We calculate terms in parentheses: +(2x2/(4(2x+1)*2(2x-1))), so:

2x2/(4(2x+1)*2(2x-1))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)



We calculate terms in parentheses: +(-4x2/(4(2x+1)*2(2x-1))), so:

-4x2/(4(2x+1)*2(2x-1))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)


We add all the numbers together, and all the variables

2x^2+(-4x^2)-7=0

We get rid of parentheses

2x^2-4x^2-7=0

We add all the numbers together, and all the variables

-2x^2-7=0

a = -2; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-2)·(-7)
Δ = -56
Delta is less than zero, so there is no solution for the equation