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1/4(2x+1)=1/2(3x-1)
We move all terms to the left:
1/4(2x+1)-(1/2(3x-1))=0
Domain of the equation: 4(2x+1)!=0
x∈R
Domain of the equation: 2(3x-1))!=0We calculate fractions
x∈R
(2x3/(4(2x+1)*2(3x-1)))+(-4x2/(4(2x+1)*2(3x-1)))=0
We calculate terms in parentheses: +(2x3/(4(2x+1)*2(3x-1))), so:
2x3/(4(2x+1)*2(3x-1))
We multiply all the terms by the denominator
2x3
We add all the numbers together, and all the variables
2x^3
We do not support expression: x^3
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