1/4(2x-3)+9=1/3(9+4x)

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Solution for 1/4(2x-3)+9=1/3(9+4x) equation: 



1/4(2x-3)+9=1/3(9+4x)

We move all terms to the left:

1/4(2x-3)+9-(1/3(9+4x))=0



Domain of the equation: 4(2x-3)!=0

x∈R





Domain of the equation: 3(9+4x))!=0

x∈R



We add all the numbers together, and all the variables

1/4(2x-3)-(1/3(4x+9))+9=0

We calculate fractions


(3x4/(4(2x-3)*3(4x+9)))+(-4x2/(4(2x-3)*3(4x+9)))+9=0



We calculate terms in parentheses: +(3x4/(4(2x-3)*3(4x+9))), so:

3x4/(4(2x-3)*3(4x+9))

We multiply all the terms by the denominator


3x4

We add all the numbers together, and all the variables

3x^4

We do not support expression: x^4

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