1/4(2x-8)=1/12(x+12)

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Solution for 1/4(2x-8)=1/12(x+12) equation: 



1/4(2x-8)=1/12(x+12)

We move all terms to the left:

1/4(2x-8)-(1/12(x+12))=0



Domain of the equation: 4(2x-8)!=0

x∈R





Domain of the equation: 12(x+12))!=0

x∈R



We calculate fractions


(12xx/(4(2x-8)*12(x+12)))+(-4x2/(4(2x-8)*12(x+12)))=0



We calculate terms in parentheses: +(12xx/(4(2x-8)*12(x+12))), so:

12xx/(4(2x-8)*12(x+12))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-4x2/(4(2x-8)*12(x+12))), so:

-4x2/(4(2x-8)*12(x+12))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)



We get rid of parentheses

-4x^2+12xx=0

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