1/4(32x-80)-3x+8=10x+28

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Solution for 1/4(32x-80)-3x+8=10x+28 equation: 



1/4(32x-80)-3x+8=10x+28

We move all terms to the left:

1/4(32x-80)-3x+8-(10x+28)=0



Domain of the equation: 4(32x-80)!=0

x∈R



We add all the numbers together, and all the variables

-3x+1/4(32x-80)-(10x+28)+8=0

We get rid of parentheses

-3x+1/4(32x-80)-10x-28+8=0

We multiply all the terms by the denominator


-3x*4(32x-80)-10x*4(32x-80)-28*4(32x-80)+8*4(32x-80)+1=0

Wy multiply elements

-12x^2(3-40x^2(3-112x(3+32x(3+1=0

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