1/4(3c+5)-1/2(2c+3)=1/2

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Solution for 1/4(3c+5)-1/2(2c+3)=1/2 equation: 



1/4(3c+5)-1/2(2c+3)=1/2

We move all terms to the left:

1/4(3c+5)-1/2(2c+3)-(1/2)=0



Domain of the equation: 4(3c+5)!=0

c∈R





Domain of the equation: 2(2c+3)!=0

c∈R



We add all the numbers together, and all the variables

1/4(3c+5)-1/2(2c+3)-(+1/2)=0

We get rid of parentheses

1/4(3c+5)-1/2(2c+3)-1/2=0

We calculate fractions


(4c2/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2)=0



We calculate terms in parentheses: +(4c2/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2), so:

4c2/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2)+(-4c3/(4(3c+5)*2(2c+3)*2

We can not solve this equation

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