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1/4(3x+1)+1/6(x+3)=3
We move all terms to the left:
1/4(3x+1)+1/6(x+3)-(3)=0
Domain of the equation: 4(3x+1)!=0
x∈R
Domain of the equation: 6(x+3)!=0We calculate fractions
x∈R
(6xx/(4(3x+1)*6(x+3))+(4x3/(4(3x+1)*6(x+3))-3=0
We can not solve this equation
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