1/4(3y+2)=1/3(2y-10)

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Solution for 1/4(3y+2)=1/3(2y-10) equation:



1/4(3y+2)=1/3(2y-10)
We move all terms to the left:
1/4(3y+2)-(1/3(2y-10))=0
Domain of the equation: 4(3y+2)!=0
y∈R
Domain of the equation: 3(2y-10))!=0
y∈R
We calculate fractions
(3y2/(4(3y+2)*3(2y-10)))+(-4y3/(4(3y+2)*3(2y-10)))=0
We calculate terms in parentheses: +(3y2/(4(3y+2)*3(2y-10))), so:
3y2/(4(3y+2)*3(2y-10))
We multiply all the terms by the denominator
3y2
We add all the numbers together, and all the variables
3y^2
Back to the equation:
+(3y^2)
We calculate terms in parentheses: +(-4y3/(4(3y+2)*3(2y-10))), so:
-4y3/(4(3y+2)*3(2y-10))
We multiply all the terms by the denominator
-4y3
We add all the numbers together, and all the variables
-4y^3
We do not support eypression: y^3

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