1/4(3y-2)=2/3(y+1)

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Solution for 1/4(3y-2)=2/3(y+1) equation: 



1/4(3y-2)=2/3(y+1)

We move all terms to the left:

1/4(3y-2)-(2/3(y+1))=0



Domain of the equation: 4(3y-2)!=0

y∈R





Domain of the equation: 3(y+1))!=0

y∈R



We calculate fractions


(3yy/(4(3y-2)*3(y+1)))+(-8y3/(4(3y-2)*3(y+1)))=0



We calculate terms in parentheses: +(3yy/(4(3y-2)*3(y+1))), so:

3yy/(4(3y-2)*3(y+1))

We multiply all the terms by the denominator


3yy

Back to the equation:

+(3yy)





We calculate terms in parentheses: +(-8y3/(4(3y-2)*3(y+1))), so:

-8y3/(4(3y-2)*3(y+1))

We multiply all the terms by the denominator


-8y3

We add all the numbers together, and all the variables

-8y^3

We do not support eypression: y^3

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