1/4(3y-2)=2/3(y+1)

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Solution for 1/4(3y-2)=2/3(y+1) equation:



1/4(3y-2)=2/3(y+1)
We move all terms to the left:
1/4(3y-2)-(2/3(y+1))=0
Domain of the equation: 4(3y-2)!=0
y∈R
Domain of the equation: 3(y+1))!=0
y∈R
We calculate fractions
(3yy/(4(3y-2)*3(y+1)))+(-8y3/(4(3y-2)*3(y+1)))=0
We calculate terms in parentheses: +(3yy/(4(3y-2)*3(y+1))), so:
3yy/(4(3y-2)*3(y+1))
We multiply all the terms by the denominator
3yy
Back to the equation:
+(3yy)
We calculate terms in parentheses: +(-8y3/(4(3y-2)*3(y+1))), so:
-8y3/(4(3y-2)*3(y+1))
We multiply all the terms by the denominator
-8y3
We add all the numbers together, and all the variables
-8y^3
We do not support eypression: y^3

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