1/4(4-x)=-3(10+2x)

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Solution for 1/4(4-x)=-3(10+2x) equation: 



1/4(4-x)=-3(10+2x)

We move all terms to the left:

1/4(4-x)-(-3(10+2x))=0



Domain of the equation: 4(4-x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-1x+4)-(-3(2x+10))=0

We multiply all the terms by the denominator


-((-3(2x+10)))*4(-1x+4)+1=0



We calculate terms in parentheses: -((-3(2x+10)))*4(-1x+4), so:

(-3(2x+10)))*4(-1x+4

We add all the numbers together, and all the variables

-1x+(-3(2x+10)))*4(+4

Back to the equation:

-(-1x+(-3(2x+10)))*4(+4)



We add all the numbers together, and all the variables

-(-1x+(-3(2x+10)))*44+1=0

We move all terms containing x to the left, all other terms to the right

-(-1x+(-3(2x+10)))*44=-1

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