1/4(4m-16)=1/2(2m+4)

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Solution for 1/4(4m-16)=1/2(2m+4) equation: 



1/4(4m-16)=1/2(2m+4)

We move all terms to the left:

1/4(4m-16)-(1/2(2m+4))=0



Domain of the equation: 4(4m-16)!=0

m∈R





Domain of the equation: 2(2m+4))!=0

m∈R



We calculate fractions


(2m2/(4(4m-16)*2(2m+4)))+(-4m4/(4(4m-16)*2(2m+4)))=0



We calculate terms in parentheses: +(2m2/(4(4m-16)*2(2m+4))), so:

2m2/(4(4m-16)*2(2m+4))

We multiply all the terms by the denominator


2m2

We add all the numbers together, and all the variables

2m^2

Back to the equation:

+(2m^2)





We calculate terms in parentheses: +(-4m4/(4(4m-16)*2(2m+4))), so:

-4m4/(4(4m-16)*2(2m+4))

We multiply all the terms by the denominator


-4m4

We add all the numbers together, and all the variables

-4m^4

We do not support empression: m^4

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