1/4(4n-3)=1/4(2n+1)

Solution for 1/4(4n-3)=1/4(2n+1) equation:

1/4(4n-3)=1/4(2n+1)

We move all terms to the left:

1/4(4n-3)-(1/4(2n+1))=0


Domain of the equation: 4(4n-3)!=0

n∈R



Domain of the equation: 4(2n+1))!=0

n∈R


We calculate fractions


(4n2/(4(4n-3)*4(2n+1)))+(-4n4/(4(4n-3)*4(2n+1)))=0


We calculate terms in parentheses: +(4n2/(4(4n-3)*4(2n+1))), so:

4n2/(4(4n-3)*4(2n+1))

We multiply all the terms by the denominator


4n2

We add all the numbers together, and all the variables

4n^2

Back to the equation:

+(4n^2)



We calculate terms in parentheses: +(-4n4/(4(4n-3)*4(2n+1))), so:

-4n4/(4(4n-3)*4(2n+1))

We multiply all the terms by the denominator


-4n4

We add all the numbers together, and all the variables

-4n^4

We do not support enpression: n^4