1/4(4x-20)+7x=3

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Solution for 1/4(4x-20)+7x=3 equation:



1/4(4x-20)+7x=3
We move all terms to the left:
1/4(4x-20)+7x-(3)=0
Domain of the equation: 4(4x-20)!=0
x∈R
We add all the numbers together, and all the variables
7x+1/4(4x-20)-3=0
We multiply all the terms by the denominator
7x*4(4x-20)-3*4(4x-20)+1=0
Wy multiply elements
28x^2(4-12x(4+1=0

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