1/4(4x-20)+7x=3

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Solution for 1/4(4x-20)+7x=3 equation: 



1/4(4x-20)+7x=3

We move all terms to the left:

1/4(4x-20)+7x-(3)=0



Domain of the equation: 4(4x-20)!=0

x∈R



We add all the numbers together, and all the variables

7x+1/4(4x-20)-3=0

We multiply all the terms by the denominator


7x*4(4x-20)-3*4(4x-20)+1=0

Wy multiply elements

28x^2(4-12x(4+1=0

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