1/4(4x-20)=1/5(25x+20)

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Solution for 1/4(4x-20)=1/5(25x+20) equation: 



1/4(4x-20)=1/5(25x+20)

We move all terms to the left:

1/4(4x-20)-(1/5(25x+20))=0



Domain of the equation: 4(4x-20)!=0

x∈R





Domain of the equation: 5(25x+20))!=0

x∈R



We calculate fractions


(5x2/(4(4x-20)*5(25x+20)))+(-4x4/(4(4x-20)*5(25x+20)))=0



We calculate terms in parentheses: +(5x2/(4(4x-20)*5(25x+20))), so:

5x2/(4(4x-20)*5(25x+20))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-4x4/(4(4x-20)*5(25x+20))), so:

-4x4/(4(4x-20)*5(25x+20))

We multiply all the terms by the denominator


-4x4

We add all the numbers together, and all the variables

-4x^4

We do not support expression: x^4

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