1/4(4x-8)-5=1/2(10x-6)

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Solution for 1/4(4x-8)-5=1/2(10x-6) equation: 



1/4(4x-8)-5=1/2(10x-6)

We move all terms to the left:

1/4(4x-8)-5-(1/2(10x-6))=0



Domain of the equation: 4(4x-8)!=0

x∈R





Domain of the equation: 2(10x-6))!=0

x∈R



We calculate fractions


(2x1/(4(4x-8)*2(10x-6)))+(-4x4/(4(4x-8)*2(10x-6)))-5=0



We calculate terms in parentheses: +(2x1/(4(4x-8)*2(10x-6))), so:

2x1/(4(4x-8)*2(10x-6))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-4x4/(4(4x-8)*2(10x-6))), so:

-4x4/(4(4x-8)*2(10x-6))

We multiply all the terms by the denominator


-4x4

We add all the numbers together, and all the variables

-4x^4

We do not support expression: x^4

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