1/4(4y+12)-y=12

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Solution for 1/4(4y+12)-y=12 equation: 



1/4(4y+12)-y=12

We move all terms to the left:

1/4(4y+12)-y-(12)=0



Domain of the equation: 4(4y+12)!=0

y∈R



We add all the numbers together, and all the variables

-1y+1/4(4y+12)-12=0

We multiply all the terms by the denominator


-1y*4(4y+12)-12*4(4y+12)+1=0

Wy multiply elements

-4y^2(4-48y(4+1=0

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