1/4(5b+12)=13+2/3b

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Solution for 1/4(5b+12)=13+2/3b equation: 



1/4(5b+12)=13+2/3b

We move all terms to the left:

1/4(5b+12)-(13+2/3b)=0



Domain of the equation: 4(5b+12)!=0

b∈R





Domain of the equation: 3b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

1/4(5b+12)-(2/3b+13)=0

We get rid of parentheses

1/4(5b+12)-2/3b-13=0

We calculate fractions


3b/(60b^2+144b)+(-8b5/(60b^2+144b)-13=0

We calculate fractions

We do not support ebpression: b^3

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