1/4(7x-4)-x=1/4-3(x+2)

Solution for 1/4(7x-4)-x=1/4-3(x+2) equation:

1/4(7x-4)-x=1/4-3(x+2)

We move all terms to the left:

1/4(7x-4)-x-(1/4-3(x+2))=0


Domain of the equation: 4(7x-4)!=0

x∈R



Domain of the equation: 4-3(x+2))!=0

We move all terms containing x to the left, all other terms to the right

-3(x+2))!=-4

x∈R


We add all the numbers together, and all the variables

-1x+1/4(7x-4)-(1/4-3(x+2))=0

We calculate fractions


-1x+(-3(x+2))+1*4)/109x+(-4x7/109x=0


We calculate terms in parentheses: +(-3(x+2)), so:

-3(x+2)

We multiply parentheses

-3x-6

Back to the equation:

+(-3x-6)


We get rid of parentheses

-1x-3x+1*4)/109x+(-4x7/109x-6=0

We calculate fractions

We do not support expression: x^8