1/4(7x-5)+6x=53

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Solution for 1/4(7x-5)+6x=53 equation: 



1/4(7x-5)+6x=53

We move all terms to the left:

1/4(7x-5)+6x-(53)=0



Domain of the equation: 4(7x-5)!=0

x∈R



We add all the numbers together, and all the variables

6x+1/4(7x-5)-53=0

We multiply all the terms by the denominator


6x*4(7x-5)-53*4(7x-5)+1=0

Wy multiply elements

24x^2(7-212x(7+1=0

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