1/4(8+20c)-2c+5=1

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Solution for 1/4(8+20c)-2c+5=1 equation: 



1/4(8+20c)-2c+5=1

We move all terms to the left:

1/4(8+20c)-2c+5-(1)=0



Domain of the equation: 4(8+20c)!=0

c∈R



We add all the numbers together, and all the variables

1/4(20c+8)-2c+5-1=0

We add all the numbers together, and all the variables

-2c+1/4(20c+8)+4=0

We multiply all the terms by the denominator


-2c*4(20c+8)+4*4(20c+8)+1=0

Wy multiply elements

-8c^2(2+16c(2+1=0

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