1/4(8-12x)+7=3

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Solution for 1/4(8-12x)+7=3 equation: 



1/4(8-12x)+7=3

We move all terms to the left:

1/4(8-12x)+7-(3)=0



Domain of the equation: 4(8-12x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-12x+8)+7-3=0

We add all the numbers together, and all the variables

1/4(-12x+8)+4=0

We multiply all the terms by the denominator


4*4(-12x+8)+1=0

Wy multiply elements

16x(-+1=0

We use the square of the difference formula

16x(-1=0

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