1/4(8-6x+12)=17

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Solution for 1/4(8-6x+12)=17 equation: 



1/4(8-6x+12)=17

We move all terms to the left:

1/4(8-6x+12)-(17)=0



Domain of the equation: 4(8-6x+12)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-6x+20)-17=0

We multiply all the terms by the denominator


-17*4(-6x+20)+1=0

Wy multiply elements

-68x(-+1=0

We use the square of the difference formula

-68x(-1=0

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