1/4(8k-4)=1/3(12-6k)

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Solution for 1/4(8k-4)=1/3(12-6k) equation: 



1/4(8k-4)=1/3(12-6k)

We move all terms to the left:

1/4(8k-4)-(1/3(12-6k))=0



Domain of the equation: 4(8k-4)!=0

k∈R





Domain of the equation: 3(12-6k))!=0

k∈R



We add all the numbers together, and all the variables

1/4(8k-4)-(1/3(-6k+12))=0

We calculate fractions


(3k(-)/(4(8k-4)*3(-6k+12)))+(-4k8/(4(8k-4)*3(-6k+12)))=0



We calculate terms in parentheses: +(3k(-)/(4(8k-4)*3(-6k+12))), so:

3k(-)/(4(8k-4)*3(-6k+12))

We add all the numbers together, and all the variables

3k0/(4(8k-4)*3(-6k+12))

We multiply all the terms by the denominator


3k0

We add all the numbers together, and all the variables

3k

Back to the equation:

+(3k)





We calculate terms in parentheses: +(-4k8/(4(8k-4)*3(-6k+12))), so:

-4k8/(4(8k-4)*3(-6k+12))

We multiply all the terms by the denominator


-4k8

We add all the numbers together, and all the variables

-4k^8

We do not support ekpression: k^8

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