1/4(8x+12)=1/2(10x-18)

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Solution for 1/4(8x+12)=1/2(10x-18) equation:



1/4(8x+12)=1/2(10x-18)
We move all terms to the left:
1/4(8x+12)-(1/2(10x-18))=0
Domain of the equation: 4(8x+12)!=0
x∈R
Domain of the equation: 2(10x-18))!=0
x∈R
We calculate fractions
(2x1/(4(8x+12)*2(10x-18)))+(-4x8/(4(8x+12)*2(10x-18)))=0
We calculate terms in parentheses: +(2x1/(4(8x+12)*2(10x-18))), so:
2x1/(4(8x+12)*2(10x-18))
We multiply all the terms by the denominator
2x1
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-4x8/(4(8x+12)*2(10x-18))), so:
-4x8/(4(8x+12)*2(10x-18))
We multiply all the terms by the denominator
-4x8
We add all the numbers together, and all the variables
-4x^8
We do not support expression: x^8

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