1/4(8x+28)-10=-1/3(15x-6)

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Solution for 1/4(8x+28)-10=-1/3(15x-6) equation: 



1/4(8x+28)-10=-1/3(15x-6)

We move all terms to the left:

1/4(8x+28)-10-(-1/3(15x-6))=0



Domain of the equation: 4(8x+28)!=0

x∈R





Domain of the equation: 3(15x-6))!=0

x∈R



We calculate fractions


(3x1/(4(8x+28)*3(15x-6)))+(-(-4x8)/(4(8x+28)*3(15x-6)))-10=0



We calculate terms in parentheses: +(3x1/(4(8x+28)*3(15x-6))), so:

3x1/(4(8x+28)*3(15x-6))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-4x8)/(4(8x+28)*3(15x-6))), so:

-(-4x8)/(4(8x+28)*3(15x-6))

We add all the numbers together, and all the variables

-(-4x^8)/(4(8x+28)*3(15x-6))

We multiply all the terms by the denominator


-(-4x^8)

We do not support expression: x^8

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