1/4(8x-12)+2x=3(2x-4)-5

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Solution for 1/4(8x-12)+2x=3(2x-4)-5 equation: 



1/4(8x-12)+2x=3(2x-4)-5

We move all terms to the left:

1/4(8x-12)+2x-(3(2x-4)-5)=0



Domain of the equation: 4(8x-12)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/4(8x-12)-(3(2x-4)-5)=0

We multiply all the terms by the denominator


2x*4(8x-12)-((3(2x-4)-5))*4(8x-12)+1=0



We calculate terms in parentheses: -((3(2x-4)-5))*4(8x-12), so:

(3(2x-4)-5))*4(8x-12



Wy multiply elements

8x^2(8-((3(2x-4)-5))*4(8x-12)+1=0

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