1/4(8x-12)+3=x-1

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Solution for 1/4(8x-12)+3=x-1 equation: 



1/4(8x-12)+3=x-1

We move all terms to the left:

1/4(8x-12)+3-(x-1)=0



Domain of the equation: 4(8x-12)!=0

x∈R



We get rid of parentheses

1/4(8x-12)-x+1+3=0

We multiply all the terms by the denominator


-x*4(8x-12)+1*4(8x-12)+3*4(8x-12)+1=0

Wy multiply elements

-4x^2(8+4x(8+12x(8+1=0

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