1/4(8x-12)=1/2(8x-40)

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Solution for 1/4(8x-12)=1/2(8x-40) equation: 



1/4(8x-12)=1/2(8x-40)

We move all terms to the left:

1/4(8x-12)-(1/2(8x-40))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 2(8x-40))!=0

x∈R



We calculate fractions


(2x8/(4(8x-12)*2(8x-40)))+(-4x8/(4(8x-12)*2(8x-40)))=0



We calculate terms in parentheses: +(2x8/(4(8x-12)*2(8x-40))), so:

2x8/(4(8x-12)*2(8x-40))

We multiply all the terms by the denominator


2x8

We add all the numbers together, and all the variables

2x^8

We do not support expression: x^8

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