1/4(8x-12)=1/7(6x-4)

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Solution for 1/4(8x-12)=1/7(6x-4) equation: 



1/4(8x-12)=1/7(6x-4)

We move all terms to the left:

1/4(8x-12)-(1/7(6x-4))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 7(6x-4))!=0

x∈R



We calculate fractions


(7x6/(4(8x-12)*7(6x-4)))+(-4x8/(4(8x-12)*7(6x-4)))=0



We calculate terms in parentheses: +(7x6/(4(8x-12)*7(6x-4))), so:

7x6/(4(8x-12)*7(6x-4))

We multiply all the terms by the denominator


7x6

We add all the numbers together, and all the variables

7x^6

We do not support expression: x^6

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