1/4(8x-12)=3/4(12x-10)

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Solution for 1/4(8x-12)=3/4(12x-10) equation: 



1/4(8x-12)=3/4(12x-10)

We move all terms to the left:

1/4(8x-12)-(3/4(12x-10))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 4(12x-10))!=0

x∈R



We calculate fractions


(4x1/(4(8x-12)*4(12x-10)))+(-12x8/(4(8x-12)*4(12x-10)))=0



We calculate terms in parentheses: +(4x1/(4(8x-12)*4(12x-10))), so:

4x1/(4(8x-12)*4(12x-10))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-12x8/(4(8x-12)*4(12x-10))), so:

-12x8/(4(8x-12)*4(12x-10))

We multiply all the terms by the denominator


-12x8

We add all the numbers together, and all the variables

-12x^8

We do not support expression: x^8

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