1/4(8x-12)=3/4(8x+8)

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Solution for 1/4(8x-12)=3/4(8x+8) equation: 



1/4(8x-12)=3/4(8x+8)

We move all terms to the left:

1/4(8x-12)-(3/4(8x+8))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 4(8x+8))!=0

x∈R



We calculate fractions


(4x8/(4(8x-12)*4(8x+8)))+(-12x8/(4(8x-12)*4(8x+8)))=0



We calculate terms in parentheses: +(4x8/(4(8x-12)*4(8x+8))), so:

4x8/(4(8x-12)*4(8x+8))

We multiply all the terms by the denominator


4x8

We add all the numbers together, and all the variables

4x^8

We do not support expression: x^8

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