1/4(8x-12)=6(1/3x-1/2)+10

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Solution for 1/4(8x-12)=6(1/3x-1/2)+10 equation: 


x in (-oo:+oo)

(1/4)*(8*x-12) = 6*((1/3)*x-(1/2))+10 // - 6*((1/3)*x-(1/2))+10

(1/4)*(8*x-12)-(6*((1/3)*x-(1/2)))-10 = 0

(1/4)*(8*x-12)-6*((1/3)*x-1/2)-10 = 0

1/4*(8*x-12)-6*(1/3*x-1/2)-10 = 0

1/4*(8*x-12)-6*(1/3*x-1/2)-10 = 0

-10 = 0

-10 = 0

x belongs to the empty set

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