1/4(8x-4)+3x=8-2(x+1)

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Solution for 1/4(8x-4)+3x=8-2(x+1) equation: 



1/4(8x-4)+3x=8-2(x+1)

We move all terms to the left:

1/4(8x-4)+3x-(8-2(x+1))=0



Domain of the equation: 4(8x-4)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/4(8x-4)-(8-2(x+1))=0

We multiply all the terms by the denominator


3x*4(8x-4)-((8-2(x+1)))*4(8x-4)+1=0



We calculate terms in parentheses: -((8-2(x+1)))*4(8x-4), so:

(8-2(x+1)))*4(8x-4



Wy multiply elements

12x^2(8-((8-2(x+1)))*4(8x-4)+1=0

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